N,n-bis(2-chloroethyl)-4-[3-[6-[6-(4-methylpiperazin-1-yl)-1h-benzimidazol-2-yl]-1h-benzimidazol-2-yl]propyl]aniline
CAS178481-68-0
N,n-bis(2-chloroethyl)-4-[3-[6-[6-(4-methylpiperazin-1-yl)-1h-benzimidazol-2-yl]-1h-benzimidazol-2-yl]propyl]aniline (CAS 178481-68-0, C32H37Cl2N7) is supplied by ChemSigma for research and manufacturing, with specification, analytical methods and batch documentation available on request.
![Chemical structure of N,n-bis(2-chloroethyl)-4-[3-[6-[6-(4-methylpiperazin-1-yl)-1h-benzimidazol-2-yl]-1h-benzimidazol-2-yl]propyl]aniline](https://chemsigma.com/chemicalStructure/17/178481-68-0.png)
- CAS No.
- 178481-68-0
- Formula
- C32H37Cl2N7
- Mol. weight
- 590.58 g/mol
Chemical Specifications
Identifiers
| CAS number | 178481-68-0 |
|---|---|
| Product name | N,n-bis(2-chloroethyl)-4-[3-[6-[6-(4-methylpiperazin-1-yl)-1h-benzimidazol-2-yl]-1h-benzimidazol-2-yl]propyl]aniline |
| Molecular formula | C32H37Cl2N7 |
| Molecular weight | 590.58 g/mol |
Packaging, Storage & Transport
| Available pack sizes | 5kg, 1kg, 500g, 100g, 50g, 10g |
|---|
Read the current safety data sheet before handling. Packaging can be adapted to the order quantity and destination.
Frequently Asked Questions
What is the CAS number of N,n-bis(2-chloroethyl)-4-[3-[6-[6-(4-methylpiperazin-1-yl)-1h-benzimidazol-2-yl]-1h-benzimidazol-2-yl]propyl]aniline?
The CAS Registry Number of N,n-bis(2-chloroethyl)-4-[3-[6-[6-(4-methylpiperazin-1-yl)-1h-benzimidazol-2-yl]-1h-benzimidazol-2-yl]propyl]aniline is 178481-68-0.
What is the molecular formula and molecular weight of N,n-bis(2-chloroethyl)-4-[3-[6-[6-(4-methylpiperazin-1-yl)-1h-benzimidazol-2-yl]-1h-benzimidazol-2-yl]propyl]aniline?
The molecular formula of N,n-bis(2-chloroethyl)-4-[3-[6-[6-(4-methylpiperazin-1-yl)-1h-benzimidazol-2-yl]-1h-benzimidazol-2-yl]propyl]aniline is C32H37Cl2N7, and its molecular weight is 590.58 g/mol.
How can I request a quotation for N,n-bis(2-chloroethyl)-4-[3-[6-[6-(4-methylpiperazin-1-yl)-1h-benzimidazol-2-yl]-1h-benzimidazol-2-yl]propyl]aniline?
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