3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID

CAS115025-90-6

3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID (CAS 115025-90-6, C19H20 O5) is supplied by ChemSigma for research and manufacturing, with specification, analytical methods and batch documentation available on request.

Chemical structure of 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID
C19H20 O5 · 398.49 g/mol
CAS No.
115025-90-6
Formula
C19H20 O5
Mol. weight
398.49 g/mol

Chemical Specifications

Identifiers

CAS number 115025-90-6
Product name 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID
Chinese name 1-萘甲基-(2-四氢呋喃甲基)丙二酸
Synonyms 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID
Chinese synonyms 1-萘甲基-(2-四氢呋喃甲基)丙二酸
Molecular formula C19H20 O5
Molecular weight 398.49 g/mol

Physical and chemical properties

Boiling Point 212.3 ( ℃ )

Packaging, Storage & Transport

Available pack sizes 5kg, 1kg, 500g, 100g, 50g, 10g

Read the current safety data sheet before handling. Packaging can be adapted to the order quantity and destination.

Frequently Asked Questions

What is the CAS number of 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID?

The CAS Registry Number of 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID is 115025-90-6. 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID is also known as 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID.

What is the molecular formula and molecular weight of 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID?

The molecular formula of 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID is C19H20 O5, and its molecular weight is 398.49 g/mol.

How can I request a quotation for 3-(2-NAPHTHALEN-1-YL-ETHYL)-3-[2-(TETRAHYDRO-PYRAN-2-YL)-ETHYL]-PENTANEDIOIC ACID?

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